Query the two cities in STATION with the shortest and longest CITY names - Hacker Rank Solution.
Query the two cities in STATION with the shortest and longest CITY names, as well as their respective lengths (i.e.: number of characters in the name). If there is more than one smallest or largest city, choose the one that comes first when ordered alphabetically.
The STATION table is described as follows:
SOLUTION :
SELECT CITY, LENGTH(CITY) AS LEN
FROM (
SELECT CITY
FROM STATION
ORDER BY LENGTH(CITY), CITY
)
WHERE ROWNUM = 1;
SELECT CITY, LENGTH(CITY) AS LEN
FROM (
SELECT CITY
FROM STATION
ORDER BY LENGTH(CITY) DESC, CITY
)
WHERE ROWNUM = 1;
We run two separate
SELECT
queries, one after the other (instead of tryingUNION
, which sometimes causes issues in SQL*Plus if not used carefully).-
Each query gets:
-
One city with the shortest name.
-
One city with the longest name.
-
-
ORDER BY LENGTH(CITY)
sorts by name length. -
ROWNUM = 1
limits the result to just one row. -
Alphabetical order is used to break ties.