In this challenge, we're going to use loops to help us do some simple math.

 Task

Given an integer, , print its first  multiples. Each multiple  (where ) should be printed on a new line in the form: N x i = result.

Input Format

A single integer, .

Output Format

Print  lines of output; each line  (where ) contains the  of  in the form:
N x i = result.

Sample Input

2

Sample Output

2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
2 x 6 = 12
2 x 7 = 14
2 x 8 = 16
2 x 9 = 18
2 x 10 = 20

Solution:

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;


public class Solution {
    public static void main(String[] args) throws IOException {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
        int N = Integer.parseInt(bufferedReader.readLine().trim());
        bufferedReader.close();
        for(int i=1;i<=10;i++)
        {
            System.out.println(N+" x "+i+" = "+N*i);
        }
    }
}